Cost function: C(x)=4x^2 + 100
Minimum average cost=?
The first derivative is 8x, did you figure that out?
At what x value does that equal 0?
You can then solve for $\displaystyle 8x=0 $
$\displaystyle \therefore 4 x^2 + 100 $ is at a minimum at $\displaystyle x = 0$,
and the value of the function at $\displaystyle x = 0$ is $\displaystyle 100$
see i understand the minimizing the average cost what my problem is the maximizing the average cost
oh and what the heck do you do when you do not have both the revenue and cost problems how do you take the derivative to figure it out if you only have one problem with two variables and one constant?...