I am confused on just one review question... involving geometric infinite series. E = sigma notation.
E(k=0 to infinity) [2(1/4)^k + 3(-1/5)^k]
Thank you!
Since both series are congergent you can do each one seperately.
First (1/4)^k is as a geometric sum: 1/(1-1/4)=4/3
Multiplied by a factor of two infront of it: 8/3
The second (-1/5)^5 is as a geometric sum: 1/(1+1/5)=5/6
Multiplied by a factor of 3 is: 3/2
When added yiedls,
3/2+8/3