For major players only: Integrate ∫ 1/√(1+x^4) dx

I broke this down using trig substitution (triangle: 1, x^2, √(x^4+1) to

∫ 1/√(2sin2ø) dø

If you could integrate in terms of ø or x it would be amazing.

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- Dec 11th 2008, 12:03 PMcdrappi2552For major players only: Integrate ∫ 1/√(1+x^4) dx...?
For major players only: Integrate ∫ 1/√(1+x^4) dx

I broke this down using trig substitution (triangle: 1, x^2, √(x^4+1) to

∫ 1/√(2sin2ø) dø

If you could integrate in terms of ø or x it would be amazing. - Dec 11th 2008, 01:11 PMLaurent
The answer is a special function, called the "inverse hyperbolic lemniscatic sine"... The inverse lemniscatic sine equals (a generalization of the arcsinus, relating to the lemniscate curve like the sinus relates to the circle...), and its hyperbolic counterpart is the function you need: . It is tightly connected to elliptic functions.

In a word: there is no expression for this anti-derivative in terms of "elementary functions"...