Where does the line <x,y>=<4t,3t> intersect the circle $\displaystyle x^2+y^2=25$?

I am quite not sure about my solution and my answer.

From <x,y>=<4t,3t>

=>> x=4t and y=3t

Then, substitute x and y to $\displaystyle x^2+y^2=25$.

==>> $\displaystyle 16t^2+9t^2=25$

==>> $\displaystyle t^2=1$

==>> $\displaystyle t=+1,-1$

At t=1,-1 is the intersection point?

And is this what the question asked?