Find u and du The indefinite integral sec2xtan2xdx I need help telling the derivative from the function apart.
Follow Math Help Forum on Facebook and Google+
Originally Posted by saraduh Find u and du The indefinite integral sec2xtan2xdx I need help telling the derivative from the function apart. Try
Would this work? sec2xtan2xdx = sin2x dx/(cos2x)^2 let u = cos2x---> du = -2sin2xdx
Originally Posted by saraduh Would this work? Mr F says: Yes. Good idea. sec2xtan2xdx = sin2x dx/(cos2x)^2 let u = cos2x---> du = -2sin2xdx ..
View Tag Cloud