Thread: Integration by substitution

Find u and du

The indefinite integral sec2xtan2xdx


I need help telling the derivative from the function apart.

Originally Posted by saraduh

Find u and du

The indefinite integral sec2xtan2xdx


I need help telling the derivative from the function apart.

Try

Would this work?


sec2xtan2xdx = sin2x dx/(cos2x)^2

let u = cos2x---> du = -2sin2xdx

Originally Posted by saraduh

Would this work? Mr F says: Yes. Good idea.


sec2xtan2xdx = sin2x dx/(cos2x)^2

let u = cos2x---> du = -2sin2xdx

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