How to check if these series converges and how to show it.
1. (n-7)/(3n^2+5n-6) when n from 1 to infinity
2.(2^2+6n-7)/(3n^5+5n^3-6) when n goes from 1 to infinity
Should I use ratio test ?
Printable View
How to check if these series converges and how to show it.
1. (n-7)/(3n^2+5n-6) when n from 1 to infinity
2.(2^2+6n-7)/(3n^5+5n^3-6) when n goes from 1 to infinity
Should I use ratio test ?
Try the limit comparison test, ifQuote:
Originally Posted by sisa
and
are infinite series and
then the series share convergence/divergence
is for the first case bsubn=1/3n and for the second case bsubb =2/n^3
Quote:
Originally Posted by sisa
do you mean
1.
2.
just thought id help with the formatting
(Yes)Quote:
Originally Posted by sisa
yes that is what I meanQuote:
Originally Posted by megamet2000do you mean
1.
2.
just thought id help with the formatting
Ok.
I calculated that in cases:
1.lim an/bn is 1 so since bn diverges to infinity, the series an diverges to infinity
2.lim an/bn is 1/3 so since bn converges to 1 an also converges to 1
Right???
I think I see how you got bn but whats an?Quote:
Originally Posted by Mathstud28
so sisa did you solve this problem? i dont understand how you found the limits..they both look like they would converge to 0.