How to check if these series converges and how to show it.

1. (n-7)/(3n^2+5n-6) when n from 1 to infinity

2.(2^2+6n-7)/(3n^5+5n^3-6) when n goes from 1 to infinity

Should I use ratio test ?

Printable View

- Dec 9th 2008, 08:25 PMsisa
How to check if these series converges and how to show it.

1. (n-7)/(3n^2+5n-6) when n from 1 to infinity

2.(2^2+6n-7)/(3n^5+5n^3-6) when n goes from 1 to infinity

Should I use ratio test ? - Dec 10th 2008, 08:56 AMMathstud28
- Dec 10th 2008, 09:12 AMsisa
is for the first case bsubn=1/3n and for the second case bsubb =2/n^3

- Dec 10th 2008, 09:15 AMmegamet2000
- Dec 10th 2008, 09:15 AMMathstud28
- Dec 10th 2008, 09:25 AMsisa
- Dec 10th 2008, 09:35 AMsisa
Ok.

I calculated that in cases:

1.lim an/bn is 1 so since bn diverges to infinity, the series an diverges to infinity

2.lim an/bn is 1/3 so since bn converges to 1 an also converges to 1

Right??? - Dec 12th 2008, 12:47 PMmegamet2000
- Dec 15th 2008, 10:05 AMmegamet2000
so sisa did you solve this problem? i dont understand how you found the limits..they both look like they would converge to 0.