how do i find f'(x) if f(x) = (integral sqrt(lnx) on top 1 on bottom) e^(t^2) for x>1?
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Originally Posted by Synth3t1c how do i find f'(x) if f(x) = (integral sqrt(lnx) on top 1 on bottom) e^(t^2) for x>1? Theorem (can be proved using chain rule and Fundamental Theorem of Calculus): If then .
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