Thread: finding f'(x) of a certain integral when x > 1?

how do i find f'(x) if f(x) = (integral sqrt(lnx) on top 1 on bottom) e^(t^2) for x>1?

Originally Posted by Synth3t1c

how do i find f'(x) if f(x) = (integral sqrt(lnx) on top 1 on bottom) e^(t^2) for x>1?

Theorem (can be proved using chain rule and Fundamental Theorem of Calculus):

If then .