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Math Help - finding f'(x) of a certain integral when x > 1?

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    finding f'(x) of a certain integral when x > 1?

    how do i find f'(x) if f(x) = (integral sqrt(lnx) on top 1 on bottom) e^(t^2) for x>1?
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  2. #2
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    Quote Originally Posted by Synth3t1c View Post
    how do i find f'(x) if f(x) = (integral sqrt(lnx) on top 1 on bottom) e^(t^2) for x>1?
    Theorem (can be proved using chain rule and Fundamental Theorem of Calculus):

    If f(x) = \int_a^{g(x)} h(t) \, dt then f'(x) = g'(x) \cdot h(g(x)).
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