
hydrostatic force
Can anyone help me with this word problem ? __
1.
A dam is inclined at an angle of 30± from the vertical and has the shape of an isoceles trapezoid 100 ft wide at the top and 50 ft wide at the bottom and with a slant height of 70 ft. Find the hydrostatic force on the dam when it is full of water.
Thanks!

nevermind i got the answer yay!!

Whoa I got this same problem.. How do you do it?

1 Attachment(s)
Since it is 30 degrees to the vertical, then we can use sin(60), which I will represent in radians.
$\displaystyle 62.4\int_{0}^{70}(xsin(\frac{\pi}{3}))(100)dx$

Thanks for your help!
I think mostly I'm having trouble drawing the picture, so I can't really get any farther than that. Would you mind redrawing with the given information?
Thanks!

christinaaa, r u also in pham's class ? lol
for finding height of dam = sqrt((70)^2  (25)^2) cos30
then for width of trapezoid = 100x/h (10050)
then u take the integral of the width which u got from above, from 0 to h

Do you have a picture?
Isn't the formula for hydrostatic force something like F = the integral of 1000 x 9.8 x area of the dam, from 0 to h?