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Math Help - I don't know what to do with these problems...

  1. #1
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    I don't know what to do with these problems...

    Hi, this is my first time using these forums, my brain is working at like half speed today for some reason... That and I can't remember what this is supposed to mean

    1) not even going to bother with this one... don't have the time to type it out right now.

    2) Find y[prime] for y^5 - x^5 = x^2 - y at the point (1,1)
    A. 7/6

    3) Find the equation of the tangent line to x = sin(t): y = 3 + t at t = pi/4. Place your answer in explicit form.
    A. y = (sqrt2)x + 2 +pi/4

    And I've found an answer close to the correct one for this question but I'm willing to bet that I've done it wrong (I did it without using calculus...), and I should be able to get the exact answer given.

    4) One plane is flying south at 300 mph and is 5 miles north of a point. A second plane is flying east at 400 mph and is 12 miles west of the same point. How fast (to the nearest mph) are the places approaching each other?
    A. 485 mph (the answer I got was 475.4 mph)

    5) tan(x + y^2) = 1.612271 expresses the relationship between the number of thousands of miles (x) I've jogged since I was born and my weight (y) in tons. If I'm currently increasing my total mileage by 6 miles per year, what is my current weight and instantaneous weight loss in points/year? To date I have jogged a thousand miles in my life.
    A. x = 1/8 tons, or 250 lbs

    Thanks
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  2. #2
    Super Member 11rdc11's Avatar
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    Quote Originally Posted by NJL72413 View Post
    Hi, this is my first time using these forums, my brain is working at like half speed today for some reason... That and I can't remember what this is supposed to mean

    1) not even going to bother with this one... don't have the time to type it out right now.

    2) Find y[prime] for y^5 - x^5 = x^2 - y at the point (1,1)
    A. 7/6

    3) Find the equation of the tangent line to x = sin(t): y = 3 + t at t = pi/4. Place your answer in explicit form.
    A. y = (sqrt2)x + 2 +pi/4

    And I've found an answer close to the correct one for this question but I'm willing to bet that I've done it wrong (I did it without using calculus...), and I should be able to get the exact answer given.

    4) One plane is flying south at 300 mph and is 5 miles north of a point. A second plane is flying east at 400 mph and is 12 miles west of the same point. How fast (to the nearest mph) are the places approaching each other?
    A. 485 mph (the answer I got was 475.4 mph)

    5) tan(x + y^2) = 1.612271 expresses the relationship between the number of thousands of miles (x) I've jogged since I was born and my weight (y) in tons. If I'm currently increasing my total mileage by 6 miles per year, what is my current weight and instantaneous weight loss in points/year? To date I have jogged a thousand miles in my life.
    A. x = 1/8 tons, or 250 lbs

    Thanks
    5y^4dy - 5x^4dx = 2xdx -dy

    5y^4dy +dy = 2xdx + 5x^4dx

    dy(5y^4 +1) = dx(2x + 5x^4)

    \frac{dy}{dx} = \frac{2x + 5x^4}{5y^4 +1}

    now plug in your point (1,1)
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  3. #3
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    Thanks, I understand that one now, but I still can't make sense of the others =\

    3) Find the equation of the tangent line to x = sin(t); y = 3 + t at t = pi/4. Place your answer in explicit form.
    A. y = (sqrt2)x + 2 +pi/4

    The equation of the tangent line is the derivative right? If that is true than I can take the derivative in parametric form, but what I get when I do that doesn't look anything like the answer. I'm guessing that I'm not even supposed to do it in parametric form but that's the only thing I can think of to do with it.

    In parametric form I come out with...

    y[prime]/x[prime] = 1/cos(t) and that looks nothing like the answer... what am I doing wrong, and am I doing anything right?
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  4. #4
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    Opalg's Avatar
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    Quote Originally Posted by NJL72413 View Post
    Thanks, I understand that one now, but I still can't make sense of the others =\

    3) Find the equation of the tangent line to x = sin(t); y = 3 + t at t = pi/4. Place your answer in explicit form.
    A. y = (sqrt2)x + 2 +pi/4

    The equation of the tangent line is the derivative right? No. The derivative is the slope of the tangent line. If that is true than I can take the derivative in parametric form, but what I get when I do that doesn't look anything like the answer. I'm guessing that I'm not even supposed to do it in parametric form but that's the only thing I can think of to do with it.

    In parametric form I come out with...

    y[prime]/x[prime] = 1/cos(t) and that looks nothing like the answer... what am I doing wrong, and am I doing anything right?
    So the slope of the tangent line at the point (sin(t),3+t) is 1/cos(t). Now you are told to put t=π/4 and then find the equation of the line with that slope going through that point. I'm sure you know how to do that.
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