1. Integration Query

Mainly part D i can do part c correct but no idea how to tackle part d -_____-
c)
$\int^4_2{e^{2x}+3}=\frac{e^{2x}}{2}+3x$

then subbing 2 and 4 gives

$[\frac{e^{8}}{2}+12]-[\frac{e^{4}}{2}+6]=\frac{1}{2}[e^{8}-e^{4}]+6$

d) would it be like subbing in 2 and 4 into the equation getting the co-ordinates

$(2,e^{4}+3) and (4,e^{8}+3)$

2. Dear Kevlar,

Area(B) = Area(big rectangle) - Area(small rectangle) - Area(A)

It can be expressed indeed as e^4 and e^8 linear combination.