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Math Help - Integration Query

  1. #1
    Junior Member
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    Integration Query


    Mainly part D i can do part c correct but no idea how to tackle part d -_____-
    c)
    \int^4_2{e^{2x}+3}=\frac{e^{2x}}{2}+3x

    then subbing 2 and 4 gives

    [\frac{e^{8}}{2}+12]-[\frac{e^{4}}{2}+6]=\frac{1}{2}[e^{8}-e^{4}]+6


    d) would it be like subbing in 2 and 4 into the equation getting the co-ordinates

    (2,e^{4}+3) and (4,e^{8}+3)
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  2. #2
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    Dear Kevlar,

    Area(B) = Area(big rectangle) - Area(small rectangle) - Area(A)

    It can be expressed indeed as e^4 and e^8 linear combination.
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