I think my answer is wrong for this problem. Iv'e work is several times and come up with this. Find $\displaystyle f(x)''$if $\displaystyle f(x)=\sqrt{2x+5}$ My answer is $\displaystyle \frac{(2x+5)^{-1/2}}{(2x+5)^{5/2}}$
Follow Math Help Forum on Facebook and Google+
Answer is $\displaystyle -\frac{1}{(2x+5)^{\frac{3}{2}}} $ $\displaystyle f'(x) = \frac{1}{(2x+5)^{\frac{1}{2}}} $ $\displaystyle f''(x) = -\frac{1}{(2x+5)^{\frac{3}{2}}} $
View Tag Cloud