I think my answer is wrong for this problem. Iv'e work is several times and come up with this.

Find $\displaystyle f(x)''$if $\displaystyle f(x)=\sqrt{2x+5}$

My answer is $\displaystyle \frac{(2x+5)^{-1/2}}{(2x+5)^{5/2}}$

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- Dec 8th 2008, 08:16 AMMcDieselSecond Derivative
I think my answer is wrong for this problem. Iv'e work is several times and come up with this.

Find $\displaystyle f(x)''$if $\displaystyle f(x)=\sqrt{2x+5}$

My answer is $\displaystyle \frac{(2x+5)^{-1/2}}{(2x+5)^{5/2}}$ - Dec 8th 2008, 08:23 AMvincisonfire
Answer is $\displaystyle -\frac{1}{(2x+5)^{\frac{3}{2}}} $

$\displaystyle f'(x) = \frac{1}{(2x+5)^{\frac{1}{2}}} $

$\displaystyle f''(x) = -\frac{1}{(2x+5)^{\frac{3}{2}}} $