# Math Help - Delta Epsilon

1. ## Delta Epsilon

if someone could tell me if I did anything wrong, or could do anything better with this problem please let me know

2. Looks good. Though if you just want to present the proof, all that scrapwork isn't necessary and you simply start from "Given $\epsilon > 0$, Let $\delta = \min \left(1, \frac{\epsilon}{6}\right)$ ..." and so on.

One thing to note: $| x - 1| \ \Leftrightarrow \ -1 < x - 1 < 1 \ \Leftrightarrow \ 4 < x + 4 < 6 \ \Rightarrow |x+4| < {\color{red}6}$

3. Thanks o_O
and sorry, but if you don't mind, I understand your note but how is it helpful here?

4. Assuming $|x-1| < 1$, we get $|x+4| < 6$ not $|x+4|<5$

5. ahh, i see now