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Math Help - Delta Epsilon

  1. #1
    Member billa's Avatar
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    Delta Epsilon

    if someone could tell me if I did anything wrong, or could do anything better with this problem please let me know

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  2. #2
    o_O
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    Looks good. Though if you just want to present the proof, all that scrapwork isn't necessary and you simply start from "Given \epsilon > 0, Let \delta = \min \left(1, \frac{\epsilon}{6}\right) ..." and so on.

    One thing to note: | x - 1| \ \Leftrightarrow \ -1 < x - 1 < 1 \ \Leftrightarrow \ 4 < x + 4 < 6 \ \Rightarrow |x+4| < {\color{red}6}
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  3. #3
    Member billa's Avatar
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    Thanks o_O
    and sorry, but if you don't mind, I understand your note but how is it helpful here?
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  4. #4
    o_O
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    Assuming |x-1| < 1, we get |x+4| < 6 not |x+4|<5
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  5. #5
    Member billa's Avatar
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    ahh, i see now
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