if someone could tell me if I did anything wrong, or could do anything better with this problem please let me know

http://www.freeimagehosting.net/uploads/5aeffbb2c1.png

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- Dec 7th 2008, 03:47 PMbillaDelta Epsilon
if someone could tell me if I did anything wrong, or could do anything better with this problem please let me know

http://www.freeimagehosting.net/uploads/5aeffbb2c1.png - Dec 7th 2008, 04:32 PMo_O
Looks good. Though if you just want to present the proof, all that scrapwork isn't necessary and you simply start from "Given $\displaystyle \epsilon > 0$, Let $\displaystyle \delta = \min \left(1, \frac{\epsilon}{6}\right)$ ..." and so on.

One thing to note: $\displaystyle | x - 1| \ \Leftrightarrow \ -1 < x - 1 < 1 \ \Leftrightarrow \ 4 < x + 4 < 6 \ \Rightarrow |x+4| < {\color{red}6}$ - Dec 7th 2008, 04:45 PMbilla
Thanks o_O

and sorry, but if you don't mind, I understand your note but how is it helpful here? - Dec 7th 2008, 05:07 PMo_O
Assuming $\displaystyle |x-1| < 1$, we get $\displaystyle |x+4| < 6$ not $\displaystyle |x+4|<5$

- Dec 7th 2008, 05:33 PMbilla
ahh, i see now