Use ol' Pythagoras,
Find D by using Pythagoras. You are given dy/dt, x, y
dx/dt is 0 because x is a constant.
Plug them in and solve for dD/dt
If the rocket shown Below is rising vertically at 268 m/s when it is 1220m up, how fast is the camera-to-rocket distance changing at that instant?
Theres a picture of a right angle triangle is below the question and the horizontal or base length is 915m
howww do u dooo thissss!!:S:S:S
A word of advice. I assume you are dealing with related rates in calc right
now. Whenever you see a right triangle, the chances are Pythagoras is going
to be involved somehow. Think about it that way. Label all the knowns you
are given and then try to find what they are asking for. In this case, they
wanted D, the hypoteneuse of the triangle. Since they asked for how fast it
is changing, we know we need dD/dt.
Sometimes they may ask for how fast the angle is changing. That is another matter using tan, but one can still incorporate Pythagoras.