I'm not looking for an answer, more or less where to start.
Here is the integral:
6/(1 + 48z - z^3) dzdydx
I can't tell where to start with this one besides pulling the 6 out of the numerator as a constant. I looked through all sorts of integration thechniques and I found no luck.
It isn't trivial to do, but by partial fractions decomposition you can. I am not saying you will get 1/1 +1/48z - 1/z^3. This method is usually covered in a calculus 2 course.
Partial fraction - Wikipedia, the free encyclopedia
Well, I didn't give any because I wanted to know how to start. I don't see a way to split it up for partial fractions though. Especially since it's a 3rd degree, 1st degree, and zero degree. The quardratic equation doesn't work, and I don't see a way to make a perfect square either.
Let me blunter than my previous post:
Your question cannot be answered properly unless you also give the integral terminals. Perhaps you should review some examples from your textbook or class notes to see why that's the case.
Here's an example of a double integral that illustrates my point:
Find .
Find .
Well I don't think the limits will necessarily change things, but the limits for the first integral are 0 and y. 0 being the lower limit and y being the upper limit. The next integral has limits of x and 4, followed by the third integral having limits of 0 and 4.