Originally Posted by

**cyberdx16** alright heres the question:

the point (1,2) lies on the curve described by the equ. x^2-xy+y^2=3

find the point other than (1,2) where the normal line to the curve at (1,2) crosses the curve.

ok i really dont know what there asking here... i mean i know how to find the normal line of the tangent line, neg recipricale(sp) of dy/dx x^2-xy+y^2=3

but what do they mean by **find the point other than (1,2) where the normal line to the curve at (1,2) crosses the curve.**

how do i find that?

do they mean find a equ of a line... meaning find the normal line from the given pt and equ?