Find the equation of the line of intersection of the two planes:

x-y=3 and x +2y+3z=0

I'm not sure if I'm doing this right.

x=3+y

3+3y+3z=0

y=-z-1

or do I take the cross product of <1,-1,0>X<1,2,3> with the point (0,0,-3)?

Thanks in advance.

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- December 5th 2008, 08:30 PMkhuezyHelp with lines of intersection
Find the equation of the line of intersection of the two planes:

x-y=3 and x +2y+3z=0

I'm not sure if I'm doing this right.

x=3+y

3+3y+3z=0

y=-z-1

or do I take the cross product of <1,-1,0>X<1,2,3> with the point (0,0,-3)?

Thanks in advance. - December 5th 2008, 09:40 PMmr fantastic
You do it like the one you were shown here: http://www.mathhelpforum.com/math-he...-equation.html

That will give you the line of intersection in parametric form.