[SOLVED] Proving sinz/z--->1 for complex numbers.
Hi everybody, thanks for reading.
I'm having trouble proving lim(sinz/z) = 1 |z-->0.
I tried using the definition with epsilons but reached no where.
The regular proof, for one variable, is of no help here. I cannot see how to prove that |sinz|<|z|. I don't even think it's true....
Also, using U(x,y) and V(x,y) isn't much help for I get pretty long two-variable functions of which it is not any easier to calculate the limit when x,y--->0.
In other words - I'm lost :-\