[SOLVED] Proving sinz/z--->1 for complex numbers.

Hi everybody, thanks for reading.

I'm having trouble proving lim(sinz/z) = 1 |z-->0.

I tried using the definition with epsilons but reached no where.

The regular proof, for one variable, is of no help here. I cannot see how to prove that |sinz|<|z|. I don't even think it's true....

Also, using U(x,y) and V(x,y) isn't much help for I get pretty long two-variable functions of which it is not any easier to calculate the limit when x,y--->0.

In other words - I'm lost :-\

Thank you!

Tomer.