Thread: Help finding derivative

(4x+3)/(3x^2+4)

Thanks.

Originally Posted by beachbunny619

(4x+3)/(3x^2+4)

Thanks.

Use the quotient rule (f'g - g'f) / g^2, where f = 4x+3 and g = 3x^2+4.

Originally Posted by ecopetition

Use the quotient rule (f'g - g'f) / g^2, where f = 4x+3 and g = 3x^2+4.

huh?

If you don't know how to do that use the product rule, (4x+3)(3x^2+4)^-1 ?

Originally Posted by ecopetition

If you don't know how to do that use the product rule, (4x+3)(3x^2+4)^-1 ?

Heres what I got:
-2*(6*x^2+9x+8)/(3*x^2+4)^2

But thats not right?