(4x+3)/(3x^2+4) Thanks.
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Originally Posted by beachbunny619 (4x+3)/(3x^2+4) Thanks. Use the quotient rule (f'g - g'f) / g^2, where f = 4x+3 and g = 3x^2+4.
Originally Posted by ecopetition Use the quotient rule (f'g - g'f) / g^2, where f = 4x+3 and g = 3x^2+4. huh?
If you don't know how to do that use the product rule, (4x+3)(3x^2+4)^-1 ?
Originally Posted by ecopetition If you don't know how to do that use the product rule, (4x+3)(3x^2+4)^-1 ? Heres what I got: -2*(6*x^2+9x+8)/(3*x^2+4)^2 But thats not right?
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