# Thread: proof of integration technique

1. ## proof of integration technique

how to prove that the integration of (x^y+b)^n can only be done without multiplying out the brakets if y=1

2. Originally Posted by hmmmm
how to prove that the integration of (x^y+b)^n can only be done without multiplying out the brakets if y=1
If y=1, then you have $\int (x+b)^n\,dx$

Applying the substitution $z=x+b$ yields the integral $\int z^n\,dz$

Can you take it from here?