how to prove that the integration of (x^y+b)^n can only be done without multiplying out the brakets if y=1
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Originally Posted by hmmmm how to prove that the integration of (x^y+b)^n can only be done without multiplying out the brakets if y=1 If y=1, then you have $\displaystyle \int (x+b)^n\,dx$ Applying the substitution $\displaystyle z=x+b$ yields the integral $\displaystyle \int z^n\,dz$ Can you take it from here?
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