I am wondering if someone can verify if I did these two derivatives of integrals correctly

$\displaystyle h(y) = \int_2^B \sin^4t (dt) B = 1/y

$

$\displaystyle h^1(y) = -sin^4(1/y)/y^2$

and

$\displaystyle g(y) = \int_A^1 \frac{u^3}{1+ u^2} du A = 1-3x $

$\displaystyle g^1(x) = -\frac{(1-3x)^2}{1+(1-3x)^2} (-3) $