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Math Help - Derivatives of Integrals

  1. #1
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    Derivatives of Integrals

    I am wondering if someone can verify if I did these two derivatives of integrals correctly


    h(y) = \int_2^B \sin^4t (dt) B = 1/y <br />
     h^1(y) = -sin^4(1/y)/y^2

    and

    g(y) = \int_A^1 \frac{u^3}{1+ u^2} du A = 1-3x
    g^1(x) = -\frac{(1-3x)^2}{1+(1-3x)^2} (-3)
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  2. #2
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    Quote Originally Posted by fishguts View Post
    I am wondering if someone can verify if I did these two derivatives of integrals correctly


    h(y) = \int_2^B \sin^4t (dt) B = 1/y <br />
     h^1(y) = -sin^4(1/y)/y^2

    and

    g(y) = \int_A^1 \frac{u^3}{1+ u^2} du A = 1-3x
    g^1(x) = -\frac{(1-3x)^2}{1+(1-3x)^2} (-3)
    Your answers are correct. The second answer can be simplified.
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