How do I find the nth derivative of x^n / (1-x) Thanks!
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Originally Posted by rhb318 How do I find the nth derivative of x^n / (1-x) Thanks! $\displaystyle \frac{x^n}{1-x}=-1-x-\cdots - x^{n-1} + \frac{1}{1-x}.$ so: $\displaystyle \left(\frac{x^n}{1-x} \right)^{(n)}=\left(\frac{1}{1-x} \right)^{(n)}=\frac{n!}{(1-x)^{n+1}}. \ \Box$
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