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Math Help - help finding inverse laplace

  1. #1
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    help finding inverse laplace

    please need help solving:

    1/((s^2)+1)^3
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by self_shattered View Post
    please need help solving:

    1/((s^2)+1)^3
    Get a decent table of Laplace transforms and look it up:

    \frac{1}{s^2+a^2}=\mathcal{L}\left( \frac{(3-a^2t^2)\sin(at)-3at \cos(at)}{8a^5} \right)

    CB
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  3. #3
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    Quote Originally Posted by self_shattered View Post
    please need help solving:

    1/((s^2)+1)^3
    You mean you wish to show:

    \mathbb{L}^{-1}\left\{\frac{1}{(s^2+1)^3}\right\}=1/8\left(3\sin(t)-3t\cos(t)-t^2\sin(t)\right)

    We can break it up into partial fractions I would guess and then take the inverse transform of each. Haven't done so yet. Can you do that?
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