Use linear approximations (or differentials) to estimate: a) sec(0.03) b)15.97 ^(3/4)
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Originally Posted by Yasmine13 Use linear approximations (or differentials) to estimate: a) sec(0.03) b)15.97 ^(3/4) $\displaystyle f(x + h) \approx f(x) + h f'(x)$. a) f(x) = sec x, x = 0, h = 0.03. b) $\displaystyle f(x) = x^{3/4}$, x = 16, h = -0.03.
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