How to find a parametrization of the curve and use it to compute the area of the interior?
please help me!
Hello,
$\displaystyle x^{2/3}+y^{2/3}=8^{2/3}$
$\displaystyle (x^{1/3})^2+(y^{1/3})^2=(8^{1/3})^2=2^2$
It's like having $\displaystyle X^2+Y^2=2^2$, for which you would make the following parametrization :
$\displaystyle X=2 \cos \theta$
$\displaystyle Y=2 \sin \theta$
So here, make $\displaystyle x^{1/3}=2 \cos \theta$ and $\displaystyle y^{1/3}=2 \sin \theta$