Find the area...

**iwonder** · Dec 3rd 2008, 08:43 PM

How to find a parametrization of the curve

and use it to compute the area of the interior?
please help me!

**Moo** · Dec 4th 2008, 11:22 AM

Hello,

Originally Posted by iwonder

How to find a parametrization of the curve

and use it to compute the area of the interior?
please help me!

$x^{2/3}+y^{2/3}=8^{2/3}$

$(x^{1/3})^2+(y^{1/3})^2=(8^{1/3})^2=2^2$

It's like having $X^2+Y^2=2^2$ , for which you would make the following parametrization :
$X=2 \cos \theta$
$Y=2 \sin \theta$

So here, make $x^{1/3}=2 \cos \theta$ and $y^{1/3}=2 \sin \theta$

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