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Thread: Find the area...

  1. Dec 3rd 2008, 09:43 PM #1
    iwonder
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    Find the area...

    How to find a parametrization of the curve and use it to compute the area of the interior?
    please help me!
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  2. Dec 4th 2008, 12:22 PM #2
    Moo
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    Hello,
    Quote Originally Posted by iwonder View Post
    How to find a parametrization of the curve and use it to compute the area of the interior?
    please help me!
    x^{2/3}+y^{2/3}=8^{2/3}

    (x^{1/3})^2+(y^{1/3})^2=(8^{1/3})^2=2^2

    It's like having X^2+Y^2=2^2, for which you would make the following parametrization :
    X=2 \cos \theta
    Y=2 \sin \theta

    So here, make x^{1/3}=2 \cos \theta and y^{1/3}=2 \sin \theta
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