Find the area...

Hello,

Quote:

Originally Posted by iwonder

How to find a parametrization of the curve http://hosted2.webwork.rochester.edu...3f5e522f11.png and use it to compute the area of the interior?
please help me!(Crying)

$x^{2/3}+y^{2/3}=8^{2/3}$

$(x^{1/3})^2+(y^{1/3})^2=(8^{1/3})^2=2^2$

It's like having $X^2+Y^2=2^2$ , for which you would make the following parametrization :
$X=2 \cos \theta$
$Y=2 \sin \theta$

So here, make $x^{1/3}=2 \cos \theta$ and $y^{1/3}=2 \sin \theta$