# Find the area...

• December 3rd 2008, 08:43 PM
iwonder
Find the area...
How to find a parametrization of the curve http://hosted2.webwork.rochester.edu...3f5e522f11.png and use it to compute the area of the interior?
• December 4th 2008, 11:22 AM
Moo
Hello,
Quote:

Originally Posted by iwonder
How to find a parametrization of the curve http://hosted2.webwork.rochester.edu...3f5e522f11.png and use it to compute the area of the interior?
$x^{2/3}+y^{2/3}=8^{2/3}$
$(x^{1/3})^2+(y^{1/3})^2=(8^{1/3})^2=2^2$
It's like having $X^2+Y^2=2^2$, for which you would make the following parametrization :
$X=2 \cos \theta$
$Y=2 \sin \theta$
So here, make $x^{1/3}=2 \cos \theta$ and $y^{1/3}=2 \sin \theta$