How to find a parametrization of the curve http://hosted2.webwork.rochester.edu...3f5e522f11.png and use it to compute the area of the interior?

please help me!(Crying)

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- Dec 3rd 2008, 08:43 PMiwonderFind the area...
How to find a parametrization of the curve http://hosted2.webwork.rochester.edu...3f5e522f11.png and use it to compute the area of the interior?

please help me!(Crying) - Dec 4th 2008, 11:22 AMMoo
Hello,

$\displaystyle x^{2/3}+y^{2/3}=8^{2/3}$

$\displaystyle (x^{1/3})^2+(y^{1/3})^2=(8^{1/3})^2=2^2$

It's like having $\displaystyle X^2+Y^2=2^2$, for which you would make the following parametrization :

$\displaystyle X=2 \cos \theta$

$\displaystyle Y=2 \sin \theta$

So here, make $\displaystyle x^{1/3}=2 \cos \theta$ and $\displaystyle y^{1/3}=2 \sin \theta$