plz help integrate

5x^2+4x+54

over

(x-4)(x^2+9)

i broke it into parts and it becomes

6/(x-4)-x/(x^2+9)

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- Dec 3rd 2008, 08:27 PMLone21integral
plz help integrate

5x^2+4x+54

over

(x-4)(x^2+9)

i broke it into parts and it becomes

6/(x-4)-x/(x^2+9) - Dec 3rd 2008, 09:12 PMnzmathmanintegral
$\displaystyle \int \left( \frac{6}{x - 4} - \frac{x}{x^2 + 9} \right) \,dx$

Both fractions can be integrating using the rule: $\displaystyle \int \frac{f\,'\,(x)}{f\,(x)} \,dx= ln[f(x)] + c$