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Math Help - Natural Logarithms

  1. #1
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    Natural Logarithms



    Have I gone about this correctly, my answere thus far is as follows,

    N = N0ekt
    ln(N) =ln( N0ekt)
    ln(N) =ln( N0) + ln(ekt) using ln(ab) = lna + lnb here a=N0, b=ekt
    ln(N) =ln( N0) + kt* ln(e) using ln(ab) = b lna here a=e, b=kt
    ln(N) =ln( N0) + kt* 1 since ln(e)=1
    ln(N) =ln( N0) + kt
    ln(N) = kt + ln( N0)
    y = mx + c where y = ln(N), m=k, x=t, c= ln(N0)

    is this ok...?
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  2. #2
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    That's OK
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  3. #3
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    great...thanks buddy
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