That's OK
Have I gone about this correctly, my answere thus far is as follows,
N = N0ekt
ln(N) =ln( N0ekt)
ln(N) =ln( N0) + ln(ekt) using ln(ab) = lna + lnb here a=N0, b=ekt
ln(N) =ln( N0) + kt* ln(e) using ln(ab) = b lna here a=e, b=kt
ln(N) =ln( N0) + kt* 1 since ln(e)=1
ln(N) =ln( N0) + kt
ln(N) = kt + ln( N0)
y = mx + c where y = ln(N), m=k, x=t, c= ln(N0)
is this ok...?