break into two integral expressions ... one using disks, the other using washers
The region R is bounded by y=sqrt[x] and y=sqrt[x(x-1)]
Find the volume by rotating around the x axis.
I used V=the integral from 0 to 1 of pi[R^2-r^2] which gave me an answer of 2pi/3 which is wrong. The answer is 7pi/6. Am I doing something wrong or do I have to use a different method?