Can someone please help me complete this problem and understand it?

Find the volume of the solid created by rotating the region bounded by the curves below around the x-axis.

$\displaystyle x=1, x=9, y=0, y= \frac{9}{\sqrt{x+5}}$

So far I have my work is as follows

$\displaystyle V=\pi \int_1^9 \frac{9}{\sqrt{x+5}^2}dx $

$\displaystyle V=\pi \int_1^9 \frac{9}{x+5}dx $

The answer is $\displaystyle 81\pi ln \frac{7}{3}$

Please help