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Math Help - Solve for upper limit of integral?

  1. #1
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    Solve for upper limit of integral?

    How would you solve for x?

    \displaystyle\int^x_0 (t^{3}-2t+3)\,dt = 4
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  2. #2
    Like a stone-audioslave ADARSH's Avatar
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    Hello,
    Quote Originally Posted by Pn0yS0ld13r View Post
    How would you solve for x?

    \displaystyle\int^x_0 (t^{3}-2t+3)\,dt = 4
     <br />
I= \int^x_0 {t^3-2t+3} <br />
    I= \int^x_0{t^3dt} - \int^x_0{2tdt}+ \int^x_0{3dt}

     <br />
I=[\frac{t^4}{4}-{t}^2+3t]^x_0 = 4<br />
    so
     <br />
\frac{x^4}{4}-{x}^2+3x-4=0<br /> <br />
    That's the equation You will get the answer as -3.091
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