∫(x^3)(x^2-1)^(3/2)dx I tried u=x^2 - 1, but then I get (1/2)du=xdx, and I have an x^3, so that's not working...what should I do?
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On the contrary, is an ideal substitution. yields Do you see why?
It's x^3 though, not x^2
I forgot to put the constant in my previous post.
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