. ..FIng g(u) ,a,b and the integral
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$\displaystyle \int_{\frac{\pi}{6}}^{\frac{\pi}{2}} \frac{cosx}{sin^7x}dx = \int_{sin(\frac{\pi}{6})}^{1} \frac{1}{u^7}du$ by using the substitution u = sin(x)
Originally Posted by sss . $\displaystyle \int_1^{e^8} \frac{dx}{x\sqrt{lnx}} = \int_0^{8} \frac{du}{\sqrt{u}}$ using the substitution $\displaystyle u =ln(x)$ I think you could do the other integral by parts
Last edited by Jason Bourne; Dec 1st 2008 at 12:17 PM.
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