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Math Help - Linearization...

  1. #1
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    Post Linearization...

    Find the linearization L(x) of f(x) = tanx at x= pi
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  2. #2
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by omibayne View Post
    Find the linearization L(x) of f(x) = tanx at x= pi
    Recall that L(x)= f(x_0)+f'(x_0)(x-x_0)

    \because f(x)=\tan(x),~f'(x)=\sec^2(x)

    Thus, f(\pi)=\tan(\pi)=0 and f'(\pi)=sec^2(\pi)=1

    Therefore, L(x)=\dots

    Can you take it from here?
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  3. #3
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    Quote Originally Posted by Chris L T521 View Post
    Recall that L(x)= f(x_0)+f'(x_0)(x-x_0)

    \because f(x)=\tan(x),~f'(x)=\sec^2(x)

    Thus, f(\pi)=\tan(\pi)=0 and f'(\pi)=sec^2(\pi)=1

    Therefore, L(x)=\dots

    Can you take it from here?

    so is it x-\pi???
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  4. #4
    Rhymes with Orange Chris L T521's Avatar
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    Quote Originally Posted by omibayne View Post
    so is it x-\pi???
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