# Math Help - Linearization...

1. ## Linearization...

Find the linearization L(x) of f(x) = tanx at x= pi

2. Originally Posted by omibayne
Find the linearization L(x) of f(x) = tanx at x= pi
Recall that $L(x)= f(x_0)+f'(x_0)(x-x_0)$

$\because f(x)=\tan(x),~f'(x)=\sec^2(x)$

Thus, $f(\pi)=\tan(\pi)=0$ and $f'(\pi)=sec^2(\pi)=1$

Therefore, $L(x)=\dots$

Can you take it from here?

3. Originally Posted by Chris L T521
Recall that $L(x)= f(x_0)+f'(x_0)(x-x_0)$

$\because f(x)=\tan(x),~f'(x)=\sec^2(x)$

Thus, $f(\pi)=\tan(\pi)=0$ and $f'(\pi)=sec^2(\pi)=1$

Therefore, $L(x)=\dots$

Can you take it from here?

so is it $x-\pi$???

4. Originally Posted by omibayne
so is it $x-\pi$???