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Math Help - integration

  1. November 30th 2008, 04:01 PM #1
    Link88
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    integration

    Can someone help me with this equation please Sinh^5x coshx dx thanks.
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  2. November 30th 2008, 05:32 PM #2
    caelum
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    Quote Originally Posted by Link88 View Post
    Can someone help me with this equation please Sinh^5x coshx dx thanks.
    \int \sinh^{5}(x) \cosh(x) dx
    Let's use u-Substitution.

    u = \sinh(x)
    du = \cosh(x) dx
    So, using these in our original integral and it's pretty simple from here.

    \int u^5 du = \frac {u^6}{6}+C
    Subbing back in u = sinh(x) and you get

    =\frac {\sinh^{6}(x)}{6}+C
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