Find all values x such that the tangent line to the graph of f(x)=4x^2 + 11x + 2 is steeper than the tangent line to g(x)=x^3

I think i get stuck while solving quadratic inequalities...

Thanks!

2. $8x + 11 > 3x^2$

$0 > 3x^2 - 8x - 11$

$0 > (3x - 11)(x + 1)$

two critical values ... $x = \frac{11}{3}$ and $x = -1$

the quadratic is negative between the two roots ...

$-1 < x < \frac{11}{3}$