Given that the summation from 1 to infinity of 1/n^2 = pi^2/6, evaluate
a) the summation from 0 to infinity of 1/(2n+1)^2
b) the summation from 0 to infinity of 1/(4n+1)^2
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I got beaten but I'll post anyway, hence your sum equals and this is
You can do the second one in the same fashion.
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