# Math Help - Can you check if I integrated correctly?

1. ## Can you check if I integrated correctly?

2. Originally Posted by No Logic Sense
The last part is not correct because you have a product
Remember that (uv)'=u'v+uv' and not u'v'
Therefore integration of u'v' does not give uv

You can integrate 32 sinx on one side and -x sinx on the other side (by parts)

3. So

????

4. Integration of 32 sinx is -32 cosx
Integration of -x sinx is x cos x - sinx (performed by parts)

therefore intergration of

$\frac{(32-x)sinx}{20}$ is

$\frac{-32\,cosx+x\, cosx-sinx}{20}$