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Originally Posted by No Logic Sense The last part is not correct because you have a product Remember that (uv)'=u'v+uv' and not u'v' Therefore integration of u'v' does not give uv You can integrate 32 sinx on one side and -x sinx on the other side (by parts)
So ????
Integration of 32 sinx is -32 cosx Integration of -x sinx is x cos x - sinx (performed by parts) therefore intergration of $\displaystyle \frac{(32-x)sinx}{20}$ is $\displaystyle \frac{-32\,cosx+x\, cosx-sinx}{20}$
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