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Math Help - Can you check if I integrated correctly?

  1. #1
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    Can you check if I integrated correctly?

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  2. #2
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    Quote Originally Posted by No Logic Sense View Post
    The last part is not correct because you have a product
    Remember that (uv)'=u'v+uv' and not u'v'
    Therefore integration of u'v' does not give uv

    You can integrate 32 sinx on one side and -x sinx on the other side (by parts)
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  3. #3
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    So



    ????
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  4. #4
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    Integration of 32 sinx is -32 cosx
    Integration of -x sinx is x cos x - sinx (performed by parts)

    therefore intergration of

    \frac{(32-x)sinx}{20} is

    \frac{-32\,cosx+x\, cosx-sinx}{20}
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