Apply newton's method to the equation $\displaystyle x^2-a=0$ to derive the following square-root algorithm: $\displaystyle Xn+1= \frac12(Xn+a/Xn)$

$\displaystyle f(x)=x^2-a$

$\displaystyle f'(x)=2x$

What's next?...

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- Nov 29th 2008, 06:30 PMFositeNewton's Method
Apply newton's method to the equation $\displaystyle x^2-a=0$ to derive the following square-root algorithm: $\displaystyle Xn+1= \frac12(Xn+a/Xn)$

$\displaystyle f(x)=x^2-a$

$\displaystyle f'(x)=2x$

What's next?... - Nov 30th 2008, 02:40 PMFosite
Come on guys... I really need help (Wondering)

- Nov 30th 2008, 02:51 PMTheEmptySet
- Nov 30th 2008, 04:37 PMFosite