Show from the definition that the function f(x) = x^3 is uniformly continuous on the interval [−1, 1].
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Originally Posted by sgarg Show from the definition that the function f(x) = x^3 is uniformly continuous on the interval [−1, 1]. let then note that So we need to bound the 2nd factor since we are on the closed interval [-1,1] this biggest it can be is 4 if x=y=1. so set So this delta will for for any I hope this clears it up good luck.
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