How do i use the difference quotient to find the first derivative of $\displaystyle f(x) = x^{5}$?
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Originally Posted by Manizzle How do i use the difference quotient to find the first derivative of $\displaystyle f(x) = x^{5}$? That is what I call tedious, you merely have to find $\displaystyle \lim_{\Delta{x}\to{0}}\frac{\left(x+\Delta{x}\righ t)^5-x^5}{\Delta{x}}$ Give it a try and report back...the answer should be $\displaystyle 5x^4$
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