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Thread: second derivative check!

  1. November 26th 2008, 07:44 PM #1
    jvignacio
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    second derivative check!

    find the second derivative of:

    y = e^xsinx
    <br /> <br /> y' = e^x(sinx+cosx)<br />

    y''= e^x(sinx+cosx)(cosx-sinx)

    correct? thank u
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  2. November 26th 2008, 08:14 PM #2
    Linnus
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    y' = e^x(sinx+cosx)
    y"= e^x(sinx+cosx)+e^x(cosx-sinx)
    y"= e^x[(sinx+cosx)+(cosx-sinx)]
    y"= e^x(2cosx)
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  3. November 26th 2008, 08:26 PM #3
    jvignacio
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    Quote Originally Posted by Linnus View Post
    y' = e^x(sinx+cosx)
    y"= e^x(sinx+cosx)+e^x(cosx-sinx)
    y"= e^x[(sinx+cosx)+(cosx-sinx)]
    y"= e^x(2cosx)

    thank u
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