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Math Help - max velocity

  1. #1
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    Question max velocity

    how do you find the maximum velocity of

    s(t)=-93.75t^3+93.75t^2+45t

    step by step to the answer would help a ton..
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  2. #2
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    Quote Originally Posted by unknown2221 View Post
    how do you find the maximum velocity of

    s(t)=-93.75t^3+93.75t^2+45t

    step by step to the answer would help a ton..
    s'(t) = 3*(-93.75)t^2 + 2*93.75t^2 +45

    s'(t) = 0

    can you solve it?

    ...

     s_1 =  \sqrt{61} /15 + 1/3

    s_2 =  -\sqrt{61} /15 + 1/3

    f''(s) = ??

    f''(s_1) < 0 => maximum

    f''(s_2) > 0 => minimum
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  3. #3
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    Don't post the same question twice. It wastes everyone's time. I already answered your question here: http://www.mathhelpforum.com/math-he...tml#post227406
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