The problem is G(x)= (x^2 - x)^1/3 When I took the first derivative I got 2x-1 / 3(x^2 - x)^2/3 I have no idea where to go from there. Any help would be appreciated. Thanks
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I know I'm supposed to set this equal to zero to get my critical numbers but I just don't know what to set to zero.
You set the derivative equal to 0 and DNE.
$\displaystyle \frac{2x-1}{3\sqrt[3]{(x^2-x)^2}}$ ... equals 0 at $\displaystyle x = \frac{1}{2}$ is undefined at $\displaystyle x = 0$ and $\displaystyle x = 1$
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