Critical Numbers *HELP*

**Afterme** · November 26th 2008, 02:06 PM

The problem is G(x)= (x^2 - x)^1/3

When I took the first derivative I got

2x-1 / 3(x^2 - x)^2/3

I have no idea where to go from there. Any help would be appreciated. Thanks

**Afterme** · November 26th 2008, 02:11 PM

I know I'm supposed to set this equal to zero to get my critical numbers but I just don't know what to set to zero.

**Linnus** · November 26th 2008, 02:27 PM

You set the derivative equal to 0 and DNE.

**skeeter** · November 26th 2008, 02:43 PM

$\frac{2x-1}{3\sqrt[3]{(x^2-x)^2}}$ ...

equals 0 at $x = \frac{1}{2}$

is undefined at $x = 0$ and $x = 1$

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