I need to obtain the volume of the region bound by y = x^2 y = 1 and the y axis by rotating it around the x axis and then about the y axis I could sure use some help if anyone has the time to explain how to attack this. Thank you
I need to obtain the volume of the region bound by y = x^2 y = 1 and the y axis by rotating it around the x axis and then about the y axis I could sure use some help if anyone has the time to explain how to attack this. Thank you
to [1]:
The solid is a cylinder with radius r = 1 and height/length = 2 (from x = -1 to x = 1):
$\displaystyle V = \int_{-1}^1\left(\pi\cdot 1^2 - \pi x^2\right)dx$
to [2]:
The solid is a kind of bowl with the parabola as cross-section:
$\displaystyle V=\int_0^1(\pi \cdot (\sqrt{y})^2)dy$
For your confirmation: The volumes are $\displaystyle \dfrac12 \pi$ and $\displaystyle \dfrac43 \pi$ .