I have to get the arch length of this function between x = 0 and x= 2

So, I used the arch length formula of the integral from 0 to 2 of sqrt[1 + (3/2x^1/2)^2] I get 3.82 but the answer is 3.53!!!! I got 8/27 (9/4x + 1)^(3/2) for my antider and evaluated it from 0 to 2. Can someone please tell me where I went wrong? Thank you.