I have to get the arch length of this function between x = 0 and x= 2
So, I used the arch length formula of the integral from 0 to 2 of sqrt[1 + (3/2x^1/2)^2] I get 3.82 but the answer is 3.53!!!! I got 8/27 (9/4x + 1)^(3/2) for my antider and evaluated it from 0 to 2. Can someone please tell me where I went wrong? Thank you.
Nov 25th 2008, 04:28 PM
We can't. Unless, you to let us know what's your solution.
Nov 25th 2008, 05:00 PM
arch length problem
When I evaluate this integral I get 3.82 for the interval of 0 to 2
Nov 25th 2008, 05:01 PM
No problem with that! But you must share your solution to see where the mistake is!
Nov 25th 2008, 05:20 PM
Thanks for looking, I figured it out I forgot to subtract the value when x is 0 which in this case has a value of 8/27. I have it!!! THanks for your time.