Hello, I have the problem: Find the area of the region outside , but inside .

So I need to figure out the limits, so I set the r's equal and got $\displaystyle \sin \theta =\frac{1}{9}$ So I have a lower limit of .11134 and the upper limit would be pi/2 right?

$\displaystyle \frac{1}{2}\int_{.11134}^{\frac{\pi}{2}}(27\sin\th eta)^2-(9+9\sin\theta)^2$

So I got the answer and then I multiplied it by two but I'm getting the wrong answer. Did I set it up right?

Thanks,

Matt