You just can't do left Riemann sum (I guess you can and get infinity), but can still do the midpoint and right Riemann sum.
I would like to know if the integral of 16/(x^2) can be approximated using a Riemann sum. The integrals are from 0 to 2. I am asking this because at one of the boundaries, (0), f(0) is undefined (approaches infinity). However, i used n=4 and got an answer of 45.5556 as the Riemann sum. But shouldn't the area be infinite? I know Riemann sums don't give exact numbers and all, but if this is the case, can the Riemann sum be used when one of the boundaries is undefined?
thanks for any help as i am completely confused right now